Q:

23. A tour bus averaged 50 miles per hoursbetween two cities on the first leg ofa trip and 45 miles per hour on thereturn trip. The return trip tookhour longer. Find the distance betweenthe two cities.​

Accepted Solution

A:
Answer:The distance between the cities is 50*4.5 = 225 miles.Step-by-step explanation:Let "t" be the time spent on the first leg at the average speed of 50 miles per hour.Then (t+0.5) is the time spent on the returning trip at the average speed of 45 miles per hour.Since the distance is the same in both directions, you have an equation50*t = 45*(t+0.5).Simplify and solve it for "t".50t = 45t + 22.5,5t = 22.5 Divide both sides by 5t = 22.5/5 = 4.5.Thus we found the time spent at the speed 50 mph. It is 4.5 hours.Thus the distance between the cities is 50*4.5 = 225 miles